(y-5)(-y-10)=y(-15-y)-100

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Solution for (y-5)(-y-10)=y(-15-y)-100 equation: 



(y-5)(-y-10)=y(-15-y)-100

We move all terms to the left:

(y-5)(-y-10)-(y(-15-y)-100)=0

We add all the numbers together, and all the variables

(y-5)(-1y-10)-(y(-1y-15)-100)=0

We multiply parentheses ..

(-1y^2-10y+5y+50)-(y(-1y-15)-100)=0



We calculate terms in parentheses: -(y(-1y-15)-100), so:

y(-1y-15)-100

We multiply parentheses

-1y^2-15y-100

Back to the equation:

-(-1y^2-15y-100)



We get rid of parentheses

-1y^2+1y^2-10y+5y+15y+50+100=0

We add all the numbers together, and all the variables

10y+150=0

We move all terms containing y to the left, all other terms to the right

10y=-150

y=-150/10

y=-15

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