(y-5)(-y-10)=y(-15-y)-100

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Solution for (y-5)(-y-10)=y(-15-y)-100 equation:



(y-5)(-y-10)=y(-15-y)-100
We move all terms to the left:
(y-5)(-y-10)-(y(-15-y)-100)=0
We add all the numbers together, and all the variables
(y-5)(-1y-10)-(y(-1y-15)-100)=0
We multiply parentheses ..
(-1y^2-10y+5y+50)-(y(-1y-15)-100)=0
We calculate terms in parentheses: -(y(-1y-15)-100), so:
y(-1y-15)-100
We multiply parentheses
-1y^2-15y-100
Back to the equation:
-(-1y^2-15y-100)
We get rid of parentheses
-1y^2+1y^2-10y+5y+15y+50+100=0
We add all the numbers together, and all the variables
10y+150=0
We move all terms containing y to the left, all other terms to the right
10y=-150
y=-150/10
y=-15

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