(y-5)/3=(y-3)/5

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Solution for (y-5)/3=(y-3)/5 equation: 



(y-5)/3=(y-3)/5

We move all terms to the left:

(y-5)/3-((y-3)/5)=0

We calculate fractions


y/()+(-((y-3)*3)/()=0



We calculate terms in parentheses: +(-((y-3)*3)/(), so:

-((y-3)*3)/(

We multiply all the terms by the denominator


-((y-3)*3)



We calculate terms in parentheses: -((y-3)*3), so:

(y-3)*3

We multiply parentheses

3y-9

Back to the equation:

-(3y-9)



We get rid of parentheses

-3y+9

Back to the equation:

+(-3y+9)



We get rid of parentheses

y/()-3y+9=0

We multiply all the terms by the denominator


y-3y*()+9*()=0

We add all the numbers together, and all the variables

y-3y*()=0

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