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(y-5+2)/(y+2)=4/5
We move all terms to the left:
(y-5+2)/(y+2)-(4/5)=0
Domain of the equation: (y+2)!=0We add all the numbers together, and all the variables
We move all terms containing y to the left, all other terms to the right
y!=-2
y∈R
(y-3)/(y+2)-(+4/5)=0
We get rid of parentheses
(y-3)/(y+2)-4/5=0
We calculate fractions
(5y-15)/(5y+10)+(-4y-8)/(5y+10)=0
We multiply all the terms by the denominator
(5y-15)+(-4y-8)=0
We get rid of parentheses
5y-4y-15-8=0
We add all the numbers together, and all the variables
y-23=0
We move all terms containing y to the left, all other terms to the right
y=23
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