(y-6)/2=(3-2y)/5

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Solution for (y-6)/2=(3-2y)/5 equation: 



(y-6)/2=(3-2y)/5

We move all terms to the left:

(y-6)/2-((3-2y)/5)=0

We add all the numbers together, and all the variables

(y-6)/2-((-2y+3)/5)=0

We calculate fractions


y/()+(-((-2y+3)*2)/()=0



We calculate terms in parentheses: +(-((-2y+3)*2)/(), so:

-((-2y+3)*2)/(

We multiply all the terms by the denominator


-((-2y+3)*2)



We calculate terms in parentheses: -((-2y+3)*2), so:

(-2y+3)*2

We multiply parentheses

-4y+6

Back to the equation:

-(-4y+6)



We get rid of parentheses

4y-6

Back to the equation:

+(4y-6)



We get rid of parentheses

y/()+4y-6=0

We multiply all the terms by the denominator


y+4y*()-6*()=0

We add all the numbers together, and all the variables

y+4y*()=0

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