(y-7)-16=2(5y+1)-4

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Solution for (y-7)-16=2(5y+1)-4 equation: 



(y-7)-16=2(5y+1)-4

We move all terms to the left:

(y-7)-16-(2(5y+1)-4)=0

We get rid of parentheses

y-(2(5y+1)-4)-7-16=0



We calculate terms in parentheses: -(2(5y+1)-4), so:

2(5y+1)-4

We multiply parentheses

10y+2-4

We add all the numbers together, and all the variables

10y-2

Back to the equation:

-(10y-2)



We add all the numbers together, and all the variables

y-(10y-2)-23=0

We get rid of parentheses

y-10y+2-23=0

We add all the numbers together, and all the variables

-9y-21=0

We move all terms containing y to the left, all other terms to the right

-9y=21

y=21/-9

y=-2+1/3

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