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(y/3)+(y/5)=(7/10)
We move all terms to the left:
(y/3)+(y/5)-((7/10))=0
We add all the numbers together, and all the variables
(+y/3)+(+y/5)-((+7/10))=0
We get rid of parentheses
y/3+y/5-((+7/10))=0
We calculate fractions
50y^2/()+30y^2/()+()/()=0
We add all the numbers together, and all the variables
50y^2/()+30y^2/()+1=0
We multiply all the terms by the denominator
50y^2+30y^2+1*()=0
We add all the numbers together, and all the variables
80y^2=0
a = 80; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·80·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$y=\frac{-b}{2a}=\frac{0}{160}=0$
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