(y/4)+(y/14)=(-9/2)

Solution for (y/4)+(y/14)=(-9/2) equation:

(y/4)+(y/14)=(-9/2)

We move all terms to the left:

(y/4)+(y/14)-((-9/2))=0

We add all the numbers together, and all the variables

(+y/4)+(+y/14)-((-9/2))=0

We get rid of parentheses

y/4+y/14-((-9/2))=0

We calculate fractions


56y^2/()+16y^2/()+()/()=0

We add all the numbers together, and all the variables

56y^2/()+16y^2/()+1=0

We multiply all the terms by the denominator


56y^2+16y^2+1*()=0

We add all the numbers together, and all the variables

72y^2=0

a = 72; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·72·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{144}=0$