(yv+2)(yv-2)=

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Solution for (yv+2)(yv-2)= equation:


Simplifying
(yv + 2)(yv + -2) = 0

Reorder the terms:
(2 + vy)(yv + -2) = 0

Reorder the terms:
(2 + vy)(-2 + vy) = 0

Multiply (2 + vy) * (-2 + vy)
(2(-2 + vy) + vy(-2 + vy)) = 0
((-2 * 2 + vy * 2) + vy(-2 + vy)) = 0
((-4 + 2vy) + vy(-2 + vy)) = 0
(-4 + 2vy + (-2 * vy + vy * vy)) = 0
(-4 + 2vy + (-2vy + v2y2)) = 0

Combine like terms: 2vy + -2vy = 0
(-4 + 0 + v2y2) = 0
(-4 + v2y2) = 0

Solving
-4 + v2y2 = 0

Solving for variable 'v'.

Move all terms containing v to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + v2y2 = 0 + 4

Combine like terms: -4 + 4 = 0
0 + v2y2 = 0 + 4
v2y2 = 0 + 4

Combine like terms: 0 + 4 = 4
v2y2 = 4

Divide each side by 'y2'.
v2 = 4y-2

Simplifying
v2 = 4y-2

Take the square root of each side:
v = {-2y-1, 2y-1}

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