(z)/(2)=(z+3)/(6)

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Solution for (z)/(2)=(z+3)/(6) equation: 



(z)/(2)=(z+3)/(6)

We move all terms to the left:

(z)/(2)-((z+3)/(6))=0

We calculate fractions


6z^2/()+(-((z+3)*2)/()=0



We calculate terms in parentheses: +(-((z+3)*2)/(), so:

-((z+3)*2)/(

We multiply all the terms by the denominator


-((z+3)*2)



We calculate terms in parentheses: -((z+3)*2), so:

(z+3)*2

We multiply parentheses

2z+6

Back to the equation:

-(2z+6)



We get rid of parentheses

-2z-6

Back to the equation:

+(-2z-6)



We get rid of parentheses

6z^2/()-2z-6=0

We multiply all the terms by the denominator


6z^2-2z*()-6*()=0

We add all the numbers together, and all the variables

6z^2-2z*()=0

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