(z+1)(-z+7)=0

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Solution for (z+1)(-z+7)=0 equation:



(z+1)(-z+7)=0
We add all the numbers together, and all the variables
(z+1)(-1z+7)=0
We multiply parentheses ..
(-1z^2+7z-1z+7)=0
We get rid of parentheses
-1z^2+7z-1z+7=0
We add all the numbers together, and all the variables
-1z^2+6z+7=0
a = -1; b = 6; c = +7;
Δ = b2-4ac
Δ = 62-4·(-1)·7
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-8}{2*-1}=\frac{-14}{-2} =+7 $
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+8}{2*-1}=\frac{2}{-2} =-1 $

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