(z+1)(z+2)=0

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Solution for (z+1)(z+2)=0 equation:


Simplifying
(z + 1)(z + 2) = 0

Reorder the terms:
(1 + z)(z + 2) = 0

Reorder the terms:
(1 + z)(2 + z) = 0

Multiply (1 + z) * (2 + z)
(1(2 + z) + z(2 + z)) = 0
((2 * 1 + z * 1) + z(2 + z)) = 0
((2 + 1z) + z(2 + z)) = 0
(2 + 1z + (2 * z + z * z)) = 0
(2 + 1z + (2z + z2)) = 0

Combine like terms: 1z + 2z = 3z
(2 + 3z + z2) = 0

Solving
2 + 3z + z2 = 0

Solving for variable 'z'.

Factor a trinomial.
(2 + z)(1 + z) = 0

Subproblem 1

Set the factor '(2 + z)' equal to zero and attempt to solve: Simplifying 2 + z = 0 Solving 2 + z = 0 Move all terms containing z to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + z = 0 + -2 Combine like terms: 2 + -2 = 0 0 + z = 0 + -2 z = 0 + -2 Combine like terms: 0 + -2 = -2 z = -2 Simplifying z = -2

Subproblem 2

Set the factor '(1 + z)' equal to zero and attempt to solve: Simplifying 1 + z = 0 Solving 1 + z = 0 Move all terms containing z to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + z = 0 + -1 Combine like terms: 1 + -1 = 0 0 + z = 0 + -1 z = 0 + -1 Combine like terms: 0 + -1 = -1 z = -1 Simplifying z = -1

Solution

z = {-2, -1}

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