(z+1)(z+5)=(z+2)(z+3)

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Solution for (z+1)(z+5)=(z+2)(z+3) equation: 



(z+1)(z+5)=(z+2)(z+3)

We move all terms to the left:

(z+1)(z+5)-((z+2)(z+3))=0

We multiply parentheses ..

(+z^2+5z+z+5)-((z+2)(z+3))=0



We calculate terms in parentheses: -((z+2)(z+3)), so:

(z+2)(z+3)

We multiply parentheses ..

(+z^2+3z+2z+6)

We get rid of parentheses

z^2+3z+2z+6

We add all the numbers together, and all the variables

z^2+5z+6

Back to the equation:

-(z^2+5z+6)



We get rid of parentheses

z^2-z^2+5z+z-5z+5-6=0

We add all the numbers together, and all the variables

z-1=0

We move all terms containing z to the left, all other terms to the right

z=1

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