(z+1)(z-2)=(z-4)(z+2)

Solution for (z+1)(z-2)=(z-4)(z+2) equation:

(z+1)(z-2)=(z-4)(z+2)

We move all terms to the left:

(z+1)(z-2)-((z-4)(z+2))=0

We multiply parentheses ..

(+z^2-2z+z-2)-((z-4)(z+2))=0


We calculate terms in parentheses: -((z-4)(z+2)), so:

(z-4)(z+2)

We multiply parentheses ..

(+z^2+2z-4z-8)

We get rid of parentheses

z^2+2z-4z-8

We add all the numbers together, and all the variables

z^2-2z-8

Back to the equation:

-(z^2-2z-8)


We get rid of parentheses

z^2-z^2-2z+z+2z-2+8=0

We add all the numbers together, and all the variables

z+6=0

We move all terms containing z to the left, all other terms to the right

z=-6