(z+1)+(1-z)i=0

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Solution for (z+1)+(1-z)i=0 equation:


Simplifying
(z + 1) + (1 + -1z) * i = 0

Reorder the terms:
(1 + z) + (1 + -1z) * i = 0

Remove parenthesis around (1 + z)
1 + z + (1 + -1z) * i = 0

Reorder the terms for easier multiplication:
1 + z + i(1 + -1z) = 0
1 + z + (1 * i + -1z * i) = 0
1 + z + (1i + -1iz) = 0

Reorder the terms:
1 + 1i + -1iz + z = 0

Solving
1 + 1i + -1iz + z = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + 1i + -1iz + -1 + z = 0 + -1

Reorder the terms:
1 + -1 + 1i + -1iz + z = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 1i + -1iz + z = 0 + -1
1i + -1iz + z = 0 + -1

Combine like terms: 0 + -1 = -1
1i + -1iz + z = -1

Add '-1z' to each side of the equation.
1i + -1iz + z + -1z = -1 + -1z

Combine like terms: z + -1z = 0
1i + -1iz + 0 = -1 + -1z
1i + -1iz = -1 + -1z

Reorder the terms:
1 + 1i + -1iz + z = -1 + -1z + 1 + z

Reorder the terms:
1 + 1i + -1iz + z = -1 + 1 + -1z + z

Combine like terms: -1 + 1 = 0
1 + 1i + -1iz + z = 0 + -1z + z
1 + 1i + -1iz + z = -1z + z

Combine like terms: -1z + z = 0
1 + 1i + -1iz + z = 0

The solution to this equation could not be determined.

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