(z+1)=2(3-2z)+17

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Solution for (z+1)=2(3-2z)+17 equation:


Simplifying
(z + 1) = 2(3 + -2z) + 17

Reorder the terms:
(1 + z) = 2(3 + -2z) + 17

Remove parenthesis around (1 + z)
1 + z = 2(3 + -2z) + 17
1 + z = (3 * 2 + -2z * 2) + 17
1 + z = (6 + -4z) + 17

Reorder the terms:
1 + z = 6 + 17 + -4z

Combine like terms: 6 + 17 = 23
1 + z = 23 + -4z

Solving
1 + z = 23 + -4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '4z' to each side of the equation.
1 + z + 4z = 23 + -4z + 4z

Combine like terms: z + 4z = 5z
1 + 5z = 23 + -4z + 4z

Combine like terms: -4z + 4z = 0
1 + 5z = 23 + 0
1 + 5z = 23

Add '-1' to each side of the equation.
1 + -1 + 5z = 23 + -1

Combine like terms: 1 + -1 = 0
0 + 5z = 23 + -1
5z = 23 + -1

Combine like terms: 23 + -1 = 22
5z = 22

Divide each side by '5'.
z = 4.4

Simplifying
z = 4.4

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