(z+1)=2(z-3)+z

Solution for (z+1)=2(z-3)+z equation:

Simplifying
(z + 1) = 2(z + -3) + z

Reorder the terms:
(1 + z) = 2(z + -3) + z

Remove parenthesis around (1 + z)
1 + z = 2(z + -3) + z

Reorder the terms:
1 + z = 2(-3 + z) + z
1 + z = (-3 * 2 + z * 2) + z
1 + z = (-6 + 2z) + z

Combine like terms: 2z + z = 3z
1 + z = -6 + 3z

Solving
1 + z = -6 + 3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-3z' to each side of the equation.
1 + z + -3z = -6 + 3z + -3z

Combine like terms: z + -3z = -2z
1 + -2z = -6 + 3z + -3z

Combine like terms: 3z + -3z = 0
1 + -2z = -6 + 0
1 + -2z = -6

Add '-1' to each side of the equation.
1 + -1 + -2z = -6 + -1

Combine like terms: 1 + -1 = 0
0 + -2z = -6 + -1
-2z = -6 + -1

Combine like terms: -6 + -1 = -7
-2z = -7

Divide each side by '-2'.
z = 3.5

Simplifying
z = 3.5