(z+2)(z+2)=0

Solution for (z+2)(z+2)=0 equation:

Simplifying
(z + 2)(z + 2) = 0

Reorder the terms:
(2 + z)(z + 2) = 0

Reorder the terms:
(2 + z)(2 + z) = 0

Multiply (2 + z) * (2 + z)
(2(2 + z) + z(2 + z)) = 0
((2 * 2 + z * 2) + z(2 + z)) = 0
((4 + 2z) + z(2 + z)) = 0
(4 + 2z + (2 * z + z * z)) = 0
(4 + 2z + (2z + z2)) = 0

Combine like terms: 2z + 2z = 4z
(4 + 4z + z2) = 0

Solving
4 + 4z + z2 = 0

Solving for variable 'z'.

Factor a trinomial.
(2 + z)(2 + z) = 0

Subproblem 1
Set the factor '(2 + z)' equal to zero and attempt to solve:

Simplifying
2 + z = 0

Solving
2 + z = 0

Move all terms containing z to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + z = 0 + -2

Combine like terms: 2 + -2 = 0
0 + z = 0 + -2
z = 0 + -2

Combine like terms: 0 + -2 = -2
z = -2

Simplifying
z = -2
Subproblem 2
Set the factor '(2 + z)' equal to zero and attempt to solve:

Simplifying
2 + z = 0

Solving
2 + z = 0

Move all terms containing z to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + z = 0 + -2

Combine like terms: 2 + -2 = 0
0 + z = 0 + -2
z = 0 + -2

Combine like terms: 0 + -2 = -2
z = -2

Simplifying
z = -2
Solution
z = {-2, -2}