(z+3)/3=5-(z+6)/5

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Solution for (z+3)/3=5-(z+6)/5 equation: 



(z+3)/3=5-(z+6)/5

We move all terms to the left:

(z+3)/3-(5-(z+6)/5)=0

We calculate fractions


z/()+(-(5-(z+6)*3)/()=0



We calculate terms in parentheses: +(-(5-(z+6)*3)/(), so:

-(5-(z+6)*3)/(

We multiply all the terms by the denominator


-(5-(z+6)*3)



We calculate terms in parentheses: -(5-(z+6)*3), so:

5-(z+6)*3

determiningTheFunctionDomain
-(z+6)*3+5

We multiply parentheses

-3z-18+5

We add all the numbers together, and all the variables

-3z-13

Back to the equation:

-(-3z-13)



We get rid of parentheses

3z+13

Back to the equation:

+(3z+13)



We get rid of parentheses

z/()+3z+13=0

We multiply all the terms by the denominator


z+3z*()+13*()=0

We add all the numbers together, and all the variables

z+3z*()=0

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