(z+4)/(z+7)+(z/4)=(2z+11)/(z+7)

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Solution for (z+4)/(z+7)+(z/4)=(2z+11)/(z+7) equation: 



(z+4)/(z+7)+(z/4)=(2z+11)/(z+7)

We move all terms to the left:

(z+4)/(z+7)+(z/4)-((2z+11)/(z+7))=0



Domain of the equation: (z+7)!=0

We move all terms containing z to the left, all other terms to the right

z!=-7

z∈R





Domain of the equation: (z+7))!=0

z∈R



We add all the numbers together, and all the variables

(z+4)/(z+7)+(+z/4)-((2z+11)/(z+7))=0

We get rid of parentheses

(z+4)/(z+7)+z/4-((2z+11)/(z+7))=0

We calculate fractions


((z+4)*4*(z+7)))/((z+7)*4*(z+7)))+(z*(z+7)*(z+7)))/((z+7)*4*(z+7)))+(-((2z+11)*(z+7)*4)/((z+7)*4*(z+7)))=0

We can not solve this equation

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