(z+5)=(4z-4)=(3z-1)

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Solution for (z+5)=(4z-4)=(3z-1) equation: 



(z+5)=(4z-4)=(3z-1)

We move all terms to the left:

(z+5)-((4z-4))=0

We get rid of parentheses

z-((4z-4))+5=0



We calculate terms in parentheses: -((4z-4)), so:

(4z-4)

We get rid of parentheses

4z-4

Back to the equation:

-(4z-4)



We get rid of parentheses

z-4z+4+5=0

We add all the numbers together, and all the variables

-3z+9=0

We move all terms containing z to the left, all other terms to the right

-3z=-9

z=-9/-3

z=+3

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