(z+50)=4z+z+10

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Solution for (z+50)=4z+z+10 equation: 



(z+50)=4z+z+10

We move all terms to the left:

(z+50)-(4z+z+10)=0

We add all the numbers together, and all the variables

(z+50)-(5z+10)=0

We get rid of parentheses

z-5z+50-10=0

We add all the numbers together, and all the variables

-4z+40=0

We move all terms containing z to the left, all other terms to the right

-4z=-40

z=-40/-4

z=+10

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