(z+6)/12+1=(2z+4)/8

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Solution for (z+6)/12+1=(2z+4)/8 equation: 


z in (-oo:+oo)

(z+6)/12+1 = (2*z+4)/8 // - (2*z+4)/8

(z+6)/12-((2*z+4)/8)+1 = 0

(z+6)/12+(-1*(2*z+4))/8+1 = 0

(8*(z+6))/(8*12)+(-1*12*(2*z+4))/(8*12)+(1*8*12)/(8*12) = 0

8*(z+6)-1*12*(2*z+4)+1*8*12 = 0

96-16*z = 0

(96-16*z)/(8*12) = 0

(96-16*z)/(8*12) = 0 // * 8*12

96-16*z = 0

96-16*z = 0 // - 96

-16*z = -96 // : -16

z = -96/(-16)

z = 6

z = 6

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