(z+7)+(3z+1)=-3(z+1)

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Solution for (z+7)+(3z+1)=-3(z+1) equation: 



(z+7)+(3z+1)=-3(z+1)

We move all terms to the left:

(z+7)+(3z+1)-(-3(z+1))=0

We get rid of parentheses

z+3z-(-3(z+1))+7+1=0



We calculate terms in parentheses: -(-3(z+1)), so:

-3(z+1)

We multiply parentheses

-3z-3

Back to the equation:

-(-3z-3)



We add all the numbers together, and all the variables

4z-(-3z-3)+8=0

We get rid of parentheses

4z+3z+3+8=0

We add all the numbers together, and all the variables

7z+11=0

We move all terms containing z to the left, all other terms to the right

7z=-11

z=-11/7

z=-1+4/7

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