(z-2)(z-(1+z))(z+(1-z))=0

Solution for (z-2)(z-(1+z))(z+(1-z))=0 equation:

Simplifying
(z + -2)(z + -1(1 + z))(z + (1 + -1z)) = 0

Reorder the terms:
(-2 + z)(z + -1(1 + z))(z + (1 + -1z)) = 0
(-2 + z)(z + (1 * -1 + z * -1))(z + (1 + -1z)) = 0
(-2 + z)(z + (-1 + -1z))(z + (1 + -1z)) = 0

Reorder the terms:
(-2 + z)(-1 + z + -1z)(z + (1 + -1z)) = 0

Combine like terms: z + -1z = 0
(-2 + z)(-1 + 0)(z + (1 + -1z)) = 0
(-2 + z)(-1)(z + (1 + -1z)) = 0

Remove parenthesis around (1 + -1z)
(-2 + z) * -1(z + 1 + -1z) = 0

Reorder the terms:
(-2 + z) * -1(1 + z + -1z) = 0

Combine like terms: z + -1z = 0
(-2 + z) * -1(1 + 0) = 0
(-2 + z) * -1(1) = 0

Reorder the terms for easier multiplication:
-1 * 1(-2 + z) = 0

Multiply -1 * 1
-1(-2 + z) = 0
(-2 * -1 + z * -1) = 0
(2 + -1z) = 0

Solving
2 + -1z = 0

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -1z = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -1z = 0 + -2
-1z = 0 + -2

Combine like terms: 0 + -2 = -2
-1z = -2

Divide each side by '-1'.
z = 2

Simplifying
z = 2