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(z-2)/(2)=(2z-3)/(3)
We move all terms to the left:
(z-2)/(2)-((2z-3)/(3))=0
We calculate fractions
z/()+(-((2z-3)*2)/()=0
We calculate terms in parentheses: +(-((2z-3)*2)/(), so:We get rid of parentheses
-((2z-3)*2)/(
We multiply all the terms by the denominator
-((2z-3)*2)
We calculate terms in parentheses: -((2z-3)*2), so:We get rid of parentheses
(2z-3)*2
We multiply parentheses
4z-6
Back to the equation:
-(4z-6)
-4z+6
Back to the equation:
+(-4z+6)
z/()-4z+6=0
We multiply all the terms by the denominator
z-4z*()+6*()=0
We add all the numbers together, and all the variables
z-4z*()=0
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