(z-2)/(2)=(2z-3)/(3)

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Solution for (z-2)/(2)=(2z-3)/(3) equation: 



(z-2)/(2)=(2z-3)/(3)

We move all terms to the left:

(z-2)/(2)-((2z-3)/(3))=0

We calculate fractions


z/()+(-((2z-3)*2)/()=0



We calculate terms in parentheses: +(-((2z-3)*2)/(), so:

-((2z-3)*2)/(

We multiply all the terms by the denominator


-((2z-3)*2)



We calculate terms in parentheses: -((2z-3)*2), so:

(2z-3)*2

We multiply parentheses

4z-6

Back to the equation:

-(4z-6)



We get rid of parentheses

-4z+6

Back to the equation:

+(-4z+6)



We get rid of parentheses

z/()-4z+6=0

We multiply all the terms by the denominator


z-4z*()+6*()=0

We add all the numbers together, and all the variables

z-4z*()=0

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