(z-2)/(z+2)=5/7

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Solution for (z-2)/(z+2)=5/7 equation: 


D( z )

z+2 = 0

z+2 = 0

z+2 = 0

z+2 = 0 // - 2

z = -2

z in (-oo:-2) U (-2:+oo)

(z-2)/(z+2) = 5/7 // - 5/7

(z-2)/(z+2)-(5/7) = 0

(z-2)/(z+2)-5/7 = 0

(7*(z-2))/(7*(z+2))+(-5*(z+2))/(7*(z+2)) = 0

7*(z-2)-5*(z+2) = 0

2*z-24 = 0

(2*z-24)/(7*(z+2)) = 0

(2*z-24)/(7*(z+2)) = 0 // * 7*(z+2)

2*z-24 = 0

2*z-24 = 0 // + 24

2*z = 24 // : 2

z = 24/2

z = 12

z = 12

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