(z-2+3i)(2z-i)=0

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Solution for (z-2+3i)(2z-i)=0 equation: 


Simplifying
(z + -2 + 3i)(2z + -1i) = 0

Reorder the terms:
(-2 + 3i + z)(2z + -1i) = 0

Reorder the terms:
(-2 + 3i + z)(-1i + 2z) = 0

Multiply (-2 + 3i + z) * (-1i + 2z)
(-2(-1i + 2z) + 3i * (-1i + 2z) + z(-1i + 2z)) = 0
((-1i * -2 + 2z * -2) + 3i * (-1i + 2z) + z(-1i + 2z)) = 0
((2i + -4z) + 3i * (-1i + 2z) + z(-1i + 2z)) = 0
(2i + -4z + (-1i * 3i + 2z * 3i) + z(-1i + 2z)) = 0

Reorder the terms:
(2i + -4z + (6iz + -3i2) + z(-1i + 2z)) = 0
(2i + -4z + (6iz + -3i2) + z(-1i + 2z)) = 0
(2i + -4z + 6iz + -3i2 + (-1i * z + 2z * z)) = 0
(2i + -4z + 6iz + -3i2 + (-1iz + 2z2)) = 0

Reorder the terms:
(2i + 6iz + -1iz + -3i2 + -4z + 2z2) = 0

Combine like terms: 6iz + -1iz = 5iz
(2i + 5iz + -3i2 + -4z + 2z2) = 0

Solving
2i + 5iz + -3i2 + -4z + 2z2 = 0

Solving for variable 'i'.

The solution to this equation could not be determined.

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