(z-2i)(z*-2i)=21-12i

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Solution for (z-2i)(z*-2i)=21-12i equation: 


Simplifying
(z + -2i)(z * -2i) = 21 + -12i

Reorder the terms:
(-2i + z)(z * -2i) = 21 + -12i

Reorder the terms for easier multiplication:
(-2i + z)(-2z * i) = 21 + -12i

Multiply z * i
(-2i + z)(-2iz) = 21 + -12i

Remove parenthesis around (-2iz)
(-2i + z) * -2iz = 21 + -12i

Reorder the terms for easier multiplication:
-2iz(-2i + z) = 21 + -12i
(-2i * -2iz + z * -2iz) = 21 + -12i

Reorder the terms:
(-2iz2 + 4i2z) = 21 + -12i
(-2iz2 + 4i2z) = 21 + -12i

Solving
-2iz2 + 4i2z = 21 + -12i

Solving for variable 'i'.

Reorder the terms:
-21 + 12i + -2iz2 + 4i2z = 21 + -12i + -21 + 12i

Reorder the terms:
-21 + 12i + -2iz2 + 4i2z = 21 + -21 + -12i + 12i

Combine like terms: 21 + -21 = 0
-21 + 12i + -2iz2 + 4i2z = 0 + -12i + 12i
-21 + 12i + -2iz2 + 4i2z = -12i + 12i

Combine like terms: -12i + 12i = 0
-21 + 12i + -2iz2 + 4i2z = 0

The solution to this equation could not be determined.

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