(z-3)/3=(z+7)/12

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Solution for (z-3)/3=(z+7)/12 equation: 



(z-3)/3=(z+7)/12

We move all terms to the left:

(z-3)/3-((z+7)/12)=0

We calculate fractions


z/()+(-((z+7)*3)/()=0



We calculate terms in parentheses: +(-((z+7)*3)/(), so:

-((z+7)*3)/(

We multiply all the terms by the denominator


-((z+7)*3)



We calculate terms in parentheses: -((z+7)*3), so:

(z+7)*3

We multiply parentheses

3z+21

Back to the equation:

-(3z+21)



We get rid of parentheses

-3z-21

Back to the equation:

+(-3z-21)



We get rid of parentheses

z/()-3z-21=0

We multiply all the terms by the denominator


z-3z*()-21*()=0

We add all the numbers together, and all the variables

z-3z*()=0

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