(z-4)/(z+3)=-(29)/(34)

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Solution for (z-4)/(z+3)=-(29)/(34) equation:


D( z )

z+3 = 0

z+3 = 0

z+3 = 0

z+3 = 0 // - 3

z = -3

z in (-oo:-3) U (-3:+oo)

(z-4)/(z+3) = -(29/34) // + 29/34

(z-4)/(z+3)+29/34 = 0

(34*(z-4))/(34*(z+3))+(29*(z+3))/(34*(z+3)) = 0

34*(z-4)+29*(z+3) = 0

63*z-49 = 0

(63*z-49)/(34*(z+3)) = 0

(63*z-49)/(34*(z+3)) = 0 // * 34*(z+3)

63*z-49 = 0

63*z-49 = 0 // + 49

63*z = 49 // : 63

z = 49/63

z = 7/9

z = 7/9

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