(z-5)(z+3)=(z+7)(z+2)

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Solution for (z-5)(z+3)=(z+7)(z+2) equation: 



(z-5)(z+3)=(z+7)(z+2)

We move all terms to the left:

(z-5)(z+3)-((z+7)(z+2))=0

We multiply parentheses ..

(+z^2+3z-5z-15)-((z+7)(z+2))=0



We calculate terms in parentheses: -((z+7)(z+2)), so:

(z+7)(z+2)

We multiply parentheses ..

(+z^2+2z+7z+14)

We get rid of parentheses

z^2+2z+7z+14

We add all the numbers together, and all the variables

z^2+9z+14

Back to the equation:

-(z^2+9z+14)



We get rid of parentheses

z^2-z^2+3z-5z-9z-15-14=0

We add all the numbers together, and all the variables

-11z-29=0

We move all terms containing z to the left, all other terms to the right

-11z=29

z=29/-11

z=-2+7/11

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