(z-7/z-9)=(2/z-9)

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Solution for (z-7/z-9)=(2/z-9) equation: 


D( z )

z = 0

z = 0

z = 0

z in (-oo:0) U (0:+oo)

z-(7/z)-9 = 2/z-9 // - 2/z-9

z-(7/z)-(2/z)-9+9 = 0

z-7*z^-1-2*z^-1-9+9 = 0

1*z^1-9*z^-1 = 0

(1*z^2-9*z^0)/(z^1) = 0 // * z^2

z^1*(1*z^2-9*z^0) = 0

z^1

z^2-9 = 0

z^2-9 = 0

DELTA = 0^2-(-9*1*4)

DELTA = 36

DELTA > 0

z = (36^(1/2)+0)/(1*2) or z = (0-36^(1/2))/(1*2)

z = 3 or z = -3

z in { -3, 3} 

z in { -3, 3 }

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