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(z-8)(z+2)-264=0
We multiply parentheses ..
(+z^2+2z-8z-16)-264=0
We get rid of parentheses
z^2+2z-8z-16-264=0
We add all the numbers together, and all the variables
z^2-6z-280=0
a = 1; b = -6; c = -280;
Δ = b2-4ac
Δ = -62-4·1·(-280)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-34}{2*1}=\frac{-28}{2} =-14 $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+34}{2*1}=\frac{40}{2} =20 $
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