(z-8)/(z-9)=1/(z-9)

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Solution for (z-8)/(z-9)=1/(z-9) equation: 


D( z )

z-9 = 0

z-9 = 0

z-9 = 0

z-9 = 0 // + 9

z = 9

z in (-oo:9) U (9:+oo)

(z-8)/(z-9) = 1/(z-9) // - 1/(z-9)

(z-8)/(z-9)-(1/(z-9)) = 0

(z-8)/(z-9)-(z-9)^-1 = 0

(z-8)/(z-9)-1/(z-9) = 0

z-8-1 = 0

z-9 = 0

(z-9)/(z-9) = 0

(z-9)/(z-9) = 0 // * z-9

z-9 = 0

z-9 = 0 // + 9

z = 9

z in { 9} 

z belongs to the empty set

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