(z-9)+(3z-13)+(z+2)=180

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Solution for (z-9)+(3z-13)+(z+2)=180 equation: 



(z-9)+(3z-13)+(z+2)=180

We move all terms to the left:

(z-9)+(3z-13)+(z+2)-(180)=0

We get rid of parentheses

z+3z+z-9-13+2-180=0

We add all the numbers together, and all the variables

5z-200=0

We move all terms containing z to the left, all other terms to the right

5z=200

z=200/5

z=40

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