(z/12)=(4/5)

Solution for (z/12)=(4/5) equation:

(z/12)=(4/5)

We move all terms to the left:

(z/12)-((4/5))=0

We add all the numbers together, and all the variables

(+z/12)-((+4/5))=0

We get rid of parentheses

z/12-((+4/5))=0

We calculate fractions


5z^2/()+()/()=0

We add all the numbers together, and all the variables

5z^2/()+1=0

We multiply all the terms by the denominator


5z^2+1*()=0

We add all the numbers together, and all the variables

5z^2=0

a = 5; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·5·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$z=\frac{-b}{2a}=\frac{0}{10}=0$