(z/15)=(28/35)

Solution for (z/15)=(28/35) equation:

(z/15)=(28/35)

We move all terms to the left:

(z/15)-((28/35))=0

We add all the numbers together, and all the variables

(+z/15)-((+28/35))=0

We get rid of parentheses

z/15-((+28/35))=0

We calculate fractions


35z^2/()+()/()=0

We add all the numbers together, and all the variables

35z^2/()+1=0

We multiply all the terms by the denominator


35z^2+1*()=0

We add all the numbers together, and all the variables

35z^2=0

a = 35; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·35·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$z=\frac{-b}{2a}=\frac{0}{70}=0$