(z/3)+(3/4)z=(9/2)(z-1)

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Solution for (z/3)+(3/4)z=(9/2)(z-1) equation:


(z/3)+(3/4)z=(9/2)(z-1)

We simplify the equation to the form, which is simple to understand 
(z/3)+(3/4)z=(9/2)*(z-1)

Remove unnecessary parentheses
 + 0.33333333333333z+( + 0.75)*z=(+4.5)*(z-1)

Reorder the terms in parentheses
 + 0.33333333333333z+( + 0.75z)=(+4.5)*(z-1)

Remove unnecessary parentheses
 + 0.33333333333333z + 0.75z=+(+4.5+)+*(+z-1+)

Reorder the terms in parentheses
multiplication of parentheses
 + 0.33333333333333z + 0.75z=(+4.5z-4.5)



Remove unnecessary parentheses
 + 0.33333333333333z + 0.75z=+4.5z-4.5

We move all terms containing z to the left and all other terms to the right. 
 + 0.33333333333333z + 0.75z-4.5z=-4.5

We simplify left and right side of the equation. 
-3.4166666666667z=-4.5

We divide both sides of the equation by -3.4166666666667 to get z. 
z=1.3170731707317

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