(z/5)-(z/4)=(z-2)/4

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Solution for (z/5)-(z/4)=(z-2)/4 equation: 



(z/5)-(z/4)=(z-2)/4

We move all terms to the left:

(z/5)-(z/4)-((z-2)/4)=0

We add all the numbers together, and all the variables

(+z/5)-(+z/4)-((z-2)/4)=0

We get rid of parentheses

z/5-z/4-((z-2)/4)=0

We calculate fractions


64z^2/()+(-5z)/()+(-((z-2)*5)/()=0



We calculate terms in parentheses: +(-((z-2)*5)/(), so:

-((z-2)*5)/(

We multiply all the terms by the denominator


-((z-2)*5)



We calculate terms in parentheses: -((z-2)*5), so:

(z-2)*5

We multiply parentheses

5z-10

Back to the equation:

-(5z-10)



We get rid of parentheses

-5z+10

Back to the equation:

+(-5z+10)



We get rid of parentheses

64z^2/()+(-5z)/()-5z+10=0

We multiply all the terms by the denominator


64z^2+(-5z)-5z*()+10*()=0

We add all the numbers together, and all the variables

64z^2+(-5z)-5z*()=0

We get rid of parentheses

64z^2-5z-5z*()=0

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