)20=8+3(12+4x)

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Solution for )20=8+3(12+4x) equation: 



)20=8+3(12+4x)

We move all terms to the left:

)20-(8+3(12+4x))=0

We add all the numbers together, and all the variables

-(8+3(4x+12))+)20=0

We add all the numbers together, and all the variables

-(8+3(4x+12))=0



We calculate terms in parentheses: -(8+3(4x+12)), so:

8+3(4x+12)

determiningTheFunctionDomain
3(4x+12)+8

We multiply parentheses

12x+36+8

We add all the numbers together, and all the variables

12x+44

Back to the equation:

-(12x+44)



We get rid of parentheses

-12x-44=0

We move all terms containing x to the left, all other terms to the right

-12x=44

x=44/-12

x=-3+2/3

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