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)5(2y-1)=(y-4)
We move all terms to the left:
)5(2y-1)-((y-4))=0
We calculate terms in parentheses: -((y-4)), so:We get rid of parentheses
(y-4)
We get rid of parentheses
y-4
Back to the equation:
-(y-4)
)5(2y-1)-y+4=0
We add all the numbers together, and all the variables
-1y+)5(2y-1)+4=0
We add all the numbers together, and all the variables
-1y+)5(2y=0
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