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)5(x-2)=3(x+4)
We move all terms to the left:
)5(x-2)-(3(x+4))=0
We calculate terms in parentheses: -(3(x+4)), so:We get rid of parentheses
3(x+4)
We multiply parentheses
3x+12
Back to the equation:
-(3x+12)
)5(x-2)-3x-12=0
We add all the numbers together, and all the variables
-3x+)5(x-2)-12=0
We add all the numbers together, and all the variables
-3x+)5(x=0
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