+(3x+8)=(7x-2)

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Solution for +(3x+8)=(7x-2) equation: 



+(3x+8)=(7x-2)

We move all terms to the left:

+(3x+8)-((7x-2))=0

We get rid of parentheses

3x-((7x-2))+8=0



We calculate terms in parentheses: -((7x-2)), so:

(7x-2)

We get rid of parentheses

7x-2

Back to the equation:

-(7x-2)



We get rid of parentheses

3x-7x+2+8=0

We add all the numbers together, and all the variables

-4x+10=0

We move all terms containing x to the left, all other terms to the right

-4x=-10

x=-10/-4

x=2+1/2

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