+(7x-8)(10x-14)+(7x-8)=180

Solution for +(7x-8)(10x-14)+(7x-8)=180 equation:

+(7x-8)(10x-14)+(7x-8)=180

We move all terms to the left:

+(7x-8)(10x-14)+(7x-8)-(180)=0

We get rid of parentheses

(7x-8)(10x-14)+7x-8-180=0

We multiply parentheses ..

(+70x^2-98x-80x+112)+7x-8-180=0

We add all the numbers together, and all the variables

(+70x^2-98x-80x+112)+7x-188=0

We get rid of parentheses

70x^2-98x-80x+7x+112-188=0

We add all the numbers together, and all the variables

70x^2-171x-76=0

a = 70; b = -171; c = -76;
Δ = b2-4ac
Δ = -1712-4·70·(-76)
Δ = 50521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-171)-\sqrt{50521}}{2*70}=\frac{171-\sqrt{50521}}{140}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-171)+\sqrt{50521}}{2*70}=\frac{171+\sqrt{50521}}{140}
$