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+1=321x^2+1=32.
We move all terms to the left:
+1-(321x^2+1)=0
We get rid of parentheses
-321x^2-1+1=0
We add all the numbers together, and all the variables
-321x^2=0
a = -321; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-321)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{-642}=0$
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