+2-(+3-2(+x+1))=2(+x-(+3+2x

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Solution for +2-(+3-2(+x+1))=2(+x-(+3+2x equation:



+2-(+3-2(+x+1))=2(+x-(+3+2x
We move all terms to the left:
+2-(+3-2(+x+1))-(2(+x-(+3+2x)=0
We add all the numbers together, and all the variables
-(+3-2(x+1))-(2(+x-(2x+3)+2=0
We calculate terms in parentheses: -(+3-2(x+1)), so:
+3-2(x+1)
determiningTheFunctionDomain -2(x+1)+3
We multiply parentheses
-2x-2+3
We add all the numbers together, and all the variables
-2x+1
Back to the equation:
-(-2x+1)
We get rid of parentheses
2x-(2(+x-(2x+3)+2-1=0

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