+7=10h2

Solution for +7=10h2 equation:

+7=10h^2

We move all terms to the left:

+7-(10h^2)=0

a = -10; b = 0; c = +7;
Δ = b2-4ac
Δ = 02-4·(-10)·7
Δ = 280
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{280}=\sqrt{4*70}=\sqrt{4}*\sqrt{70}=2\sqrt{70}$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{70}}{2*-10}=\frac{0-2\sqrt{70}}{-20}
=-\frac{2\sqrt{70}}{-20}
=-\frac{\sqrt{70}}{-10}
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{70}}{2*-10}=\frac{0+2\sqrt{70}}{-20}
=\frac{2\sqrt{70}}{-20}
=\frac{\sqrt{70}}{-10}
$