+=-2e(3-5e)

Solution for +=-2e(3-5e) equation:

+=-2e(3-5e)

We move all terms to the left:

+-(-2e(3-5e))=0

We add all the numbers together, and all the variables

-(-2e(-5e+3))+=0

We add all the numbers together, and all the variables

-(-2e(-5e+3))=0


We calculate terms in parentheses: -(-2e(-5e+3)), so:

-2e(-5e+3)

We multiply parentheses

10e^2-6e

Back to the equation:

-(10e^2-6e)


We get rid of parentheses

-10e^2+6e=0

a = -10; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·(-10)·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*-10}=\frac{-12}{-20}
=3/5
$
$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*-10}=\frac{0}{-20}
=0
$