-((3a)/(a+12))=9/(a-18)

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Solution for -((3a)/(a+12))=9/(a-18) equation:


D( a )

a+12 = 0

a-18 = 0

a+12 = 0

a+12 = 0

a+12 = 0 // - 12

a = -12

a-18 = 0

a-18 = 0

a-18 = 0 // + 18

a = 18

a in (-oo:-12) U (-12:18) U (18:+oo)

-((3*a)/(a+12)) = 9/(a-18) // - 9/(a-18)

-((3*a)/(a+12))-(9/(a-18)) = 0

-3*a*(a+12)^-1-9*(a-18)^-1 = 0

(-3*a)/(a+12)-9/(a-18) = 0

(-3*a*(a-18))/((a+12)*(a-18))+(-9*(a+12))/((a+12)*(a-18)) = 0

-3*a*(a-18)-9*(a+12) = 0

45*a-3*a^2-108 = 0

45*a-3*a^2-108 = 0

3*(15*a-a^2-36) = 0

15*a-a^2-36 = 0

DELTA = 15^2-(-36*(-1)*4)

DELTA = 81

DELTA > 0

a = (81^(1/2)-15)/(-1*2) or a = (-81^(1/2)-15)/(-1*2)

a = 3 or a = 12

3*(a-3)*(a-12) = 0

(3*(a-3)*(a-12))/((a+12)*(a-18)) = 0

(3*(a-3)*(a-12))/((a+12)*(a-18)) = 0 // * (a+12)*(a-18)

3*(a-3)*(a-12) = 0

( a-12 )

a-12 = 0 // + 12

a = 12

( a-3 )

a-3 = 0 // + 3

a = 3

a in { 12, 3 }

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