-(-1-4x)=4(x+2)2+6

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Solution for -(-1-4x)=4(x+2)2+6 equation: 



-(-1-4x)=4(x+2)2+6

We move all terms to the left:

-(-1-4x)-(4(x+2)2+6)=0

We add all the numbers together, and all the variables

-(-4x-1)-(4(x+2)2+6)=0

We get rid of parentheses

4x-(4(x+2)2+6)+1=0



We calculate terms in parentheses: -(4(x+2)2+6), so:

4(x+2)2+6

We multiply parentheses

8x+16+6

We add all the numbers together, and all the variables

8x+22

Back to the equation:

-(8x+22)



We get rid of parentheses

4x-8x-22+1=0

We add all the numbers together, and all the variables

-4x-21=0

We move all terms containing x to the left, all other terms to the right

-4x=21

x=21/-4

x=-5+1/4

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